Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Need explanation for: - Oscillations and Waves - JEE Main-9

A wave is represented by the equation: y = a\sin(0.01x-2t), where a and x are in cm. Velocity of propogation of wave is

  • Option 1)

    10 cm/s

  • Option 2)

    50 cm/s

  • Option 3)

    100 cm/s

  • Option 4)

    200 cm/s

 

Answers (1)

v = \frac{\omega }{k} = \frac{co-efficient of t}{co-efficient of x} = \frac{2}{0.01} = 200 cm/sec

 

Speed of sinusoidal wave -

Wave Speed

\tfrac{dx}{dt}= V=\frac{\omega }{k}
 

- wherein

\omega = 2\pi \nu

K= \frac{2\pi }{\lambda }

 

 

 


Option 1)

10 cm/s

This is incorrect.

Option 2)

50 cm/s

This is incorrect.

Option 3)

100 cm/s

This is incorrect.

Option 4)

200 cm/s

This is correct.

Posted by

subam

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 session 2 answer key out for BArch, BPlanning; response sheet on jeemain.nta.nic.in
anam-khan

JEE Mains 2025 Paper 2 Answer Key LIVE: BArch final answer key PDF expected soon at jeemain.nta.nic.in
anam-khan

JEE Main 2025 response sheet errors: Delhi HC allows student to apply for JEE Adv, seeks NTA explanation

Latest Question