Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

A splid sphere and cylinder of identical radii approah an incline with the same liner velocity (see figure ). Both roll without slipping all throughout. The two climb maximum hrights h_{sph} and h_{cyl} on the incline. The ratio \frac{h_{sph}}{h_{cyl}} is given by:

  • Option 1)

    \frac{2}{\sqrt{5}}

  • Option 2)

    1

  • Option 3)

    \frac{14}{15}

  • Option 4)

    \frac{4}{5}

Answers (1)

best_answer

V=wR

For sphere 

mgh_{1}=k_{1}=\frac{1}{2}Iw^{2}+\frac{1}{2}mv^{2}

           =\frac{1}{2}\times \frac{2}{5}mR^{2}w^{2}+\frac{1}{2}mv^{2}

           =\left ( \frac{1}{5}+\frac{1}{2} \right )mv^{2}=\frac{7}{10}mv^{2}

For solid cylinder

mgh_{2}=k_{2}=\frac{1}{2}mv^{2}+\frac{1}{2}\frac{mR^{2}}{2}w^{2}= mv^{2}\left ( \frac{1}{2}+\frac{1}{4} \right )=\frac{3}{4}mv^{2}

\frac{mgh_{1}}{mgh_{2}}=\frac{k_{1}}{k_{2}}=\frac{\frac{7}{10}mv^{2}}{\frac{3}{4}mv^{2}}=\frac{28}{30}=\frac{14}{15}

 


Option 1)

\frac{2}{\sqrt{5}}

Option 2)

1

Option 3)

\frac{14}{15}

Option 4)

\frac{4}{5}

Posted by

solutionqc

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question