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Need explanation for: The final product formed when Methyl amine is treated with NaNO2 and HCl is

 The final product formed when Methyl  amine is treated with NaNO2 and HCl is

  • Option 1)

      Diazomethane  
     

     

  • Option 2)

      Methylalcohol   
     

  • Option 3)

     Methylcyanide   
     

  • Option 4)

    Nitromethane  

 
Answers (1)
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As we learnt in 

Reaction with Nitrous Acid Primary Amines -

Primary amines react with nitrous acid to produce diazonium ion.

- wherein

R-NH_{2}+HNO_{2}\rightarrow R-N^{\oplus }\equiv N

 

ArNH_{2}+HNO_{2}\rightarrow Ar-N^{\oplus }\equiv N:

 

The values of ionization potential of an element decrease as the atomic size increases. Also, removal of electron from half or full filled atoms require more energy than expected with maximum in noble gases.

Finally, IE increases along a period and decreases down the group.

So, the order is Ba <Ca< Se< S < Ar

CH_{3}-NH_{2}\xrightarrow{}{NaNO_{3}/HCl}CH_{3}-OH

                             Methylalcohol

Reaction of aliphatic primary amines with nitrous acid to produce alcohol.

R-NH_{2} \xrightarrow[0-5\degree C]{NaNO_{2}/HCl}R-OH


Option 1)

  Diazomethane  
 

 

This option is incorrect

Option 2)

  Methylalcohol   
 

This option is correct

Option 3)

 Methylcyanide   
 

This option is incorrect

Option 4)

Nitromethane  

This option is incorrect

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