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The force between two charges is 120N. If the distance between the charges is doubled, then the force will be

  • Option 1)

    60N

  • Option 2)

    30N

  • Option 3)

    40N

  • Option 4)

    15N

 

Answers (1)

best_answer

As we learnt in 

Coulombic force -

F\propto Q_{1}Q_{2}=F\propto \frac{Q_{1}Q_{2}}{r^{2}}=F=\frac{KQ_{1}Q_{2}}{r^{2}}

- wherein

K - proportionality Constant 

Q1 and Q2 are two Point charge

 

 F \propto \frac{1}{r^{2}}

F_{1} = \frac{Kq}{r^{2}}\ \ and \ \ F_{2} = \frac{Kq}{4r^{2}} = \frac{F_{1}}{4} = 30 \ N


Option 1)

60N

This option is incorrect

Option 2)

30N

This option is correct

Option 3)

40N

This option is incorrect

Option 4)

15N

This option is incorrect

Posted by

prateek

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