The force between two charges is 120N. If the distance between the charges is doubled, then the force will be

  • Option 1)

    60N

  • Option 2)

    30N

  • Option 3)

    40N

  • Option 4)

    15N

 

Answers (1)

As we learnt in 

Coulombic force -

F\propto Q_{1}Q_{2}=F\propto \frac{Q_{1}Q_{2}}{r^{2}}=F=\frac{KQ_{1}Q_{2}}{r^{2}}

- wherein

K - proportionality Constant 

Q1 and Q2 are two Point charge

 

 F \propto \frac{1}{r^{2}}

F_{1} = \frac{Kq}{r^{2}}\ \ and \ \ F_{2} = \frac{Kq}{4r^{2}} = \frac{F_{1}}{4} = 30 \ N


Option 1)

60N

This option is incorrect

Option 2)

30N

This option is correct

Option 3)

40N

This option is incorrect

Option 4)

15N

This option is incorrect

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