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  • Need explanation for: The prong of an electrically operated tunning fork is connected to a long string of M = 1kg/m and tension 25 N. The max velocity of the prong is 1 cm/s, then the average power needed to drive the prong is

The prong of an electrically operated tunning fork is connected to a long string of M = 1kg/m and tension 25 N. The max velocity of the prong is 1 cm/s, then the average power needed to drive the prong is 

  • Option 1)

    5\times 10^{-4} W

  • Option 2)

    2.5\times 10^{-4} W

  • Option 3)

    10^{-4} W

  • Option 4)

    10^{-3} W

 

Answers (1)

best_answer

v = \sqrt \frac {F}{\mu} = 5 m/s

P = \frac{1}{2} \mu v (\omega A)^{2} = \frac{1}{2} X 1 X 5 (1 X 10 ^{-2}) ^{2} = 2.5 X 10 ^{-4} W

 

Rate of energy transfer on string by sinusiodal wave -

\rho = \frac{1}{2}\mu \omega ^{2}A^{2}V
 

- wherein

\mu = linear mass density

\omega = angular frequency

A = Amplitude

V = Wave speed

 

 

 


Option 1)

5\times 10^{-4} W

This is incorrect.

Option 2)

2.5\times 10^{-4} W

This is correct.

Option 3)

10^{-4} W

This is incorrect.

Option 4)

10^{-3} W

This is incorrect.

Posted by

divya.saini

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