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  • Need explanation for: The species that can have a trans-isomer is:( en = ethane-1,2-diamine, ox = oxalate)

The species that can have a trans-isomer is:

( en = ethane-1,2-diamine, ox = oxalate) 

  • Option 1)

    [Zn(en)Cl_{2}]

  • Option 2)

    [Pt(en)Cl_{2}]

  • Option 3)

    [Cr(en)_{2}(ox)]^{+}

  • Option 4)

    [Pt(en)_{2}Cl_{2}]^{2+}

Answers (1)

best_answer

(1) [Zn(en)Cl_{2}] :

 : sp^{3} hybridised , therefore no trans-isomer is possible.

(2) [Pt(en)Cl_{2}]

: Bidentate ligand will be co-ordinating at 90^{\circ} in square planar complex.

                                 Thus, no trans-isomer is possible.

(3) [Cr(en)_{2}(ox)]^{+}

: In this compound as well, no trans-isommer is possible.

(4) [Pt(en)_{2}Cl_{2}]^{2+}

In this compound both trans and cis are possible.

\therefore option (4) is correct.


Option 1)

[Zn(en)Cl_{2}]

Option 2)

[Pt(en)Cl_{2}]

Option 3)

[Cr(en)_{2}(ox)]^{+}

Option 4)

[Pt(en)_{2}Cl_{2}]^{2+}
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