The species that can have a trans-isomer is:

( en = ethane-1,2-diamine, ox = oxalate) 

  • Option 1)

    [Zn(en)Cl_{2}]

  • Option 2)

    [Pt(en)Cl_{2}]

  • Option 3)

    [Cr(en)_{2}(ox)]^{+}

  • Option 4)

    [Pt(en)_{2}Cl_{2}]^{2+}

Answers (1)

(1) [Zn(en)Cl_{2}] :

 sp^{3} hybridised , therefore no trans-isomer is possible.

(2) [Pt(en)Cl_{2}]

: Bidentate ligand will be co-ordinating at 90^{\circ} in square planar complex.

                                 Thus, no trans-isomer is possible.

(3) [Cr(en)_{2}(ox)]^{+}

: In this compound as well, no trans-isommer is possible.

(4) [Pt(en)_{2}Cl_{2}]^{2+}

In this compound both trans and cis are possible.

\therefore option (4) is correct.


Option 1)

[Zn(en)Cl_{2}]

Option 2)

[Pt(en)Cl_{2}]

Option 3)

[Cr(en)_{2}(ox)]^{+}

Option 4)

[Pt(en)_{2}Cl_{2}]^{2+}

Most Viewed Questions

Preparation Products

Knockout JEE Main (Six Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan.

₹ 9999/- ₹ 8499/-
Buy Now
Knockout JEE Main (Nine Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan.

₹ 13999/- ₹ 12499/-
Buy Now
Knockout JEE Main (One Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan.

₹ 2999/- ₹ 1999/-
Buy Now
Knockout JEE Main (Twelve Months Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan.

₹ 19999/- ₹ 14499/-
Buy Now
Knockout JEE Main (Eight Months Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan.

₹ 15999/- ₹ 12499/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions