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The unit of Ebulioscopic Contant is

Option 1)
K Kg mol^-1 or K(molality)^-1

Option 2)
mol Kg K^-1 or K^-1 (molality)

Option 3)
Kg mol^-1 K^-1 or K^-1(molality)^-1

Option 4)
K Mol Kg^-1or K (molality)

Answers (1)

Dependence of K_{b} -

$K_{b}$ depends only on nature of solvent.

$K_{b} =\frac{ RT_{b}^{2}\cdot M}{1000\, \Delta H_{vop}}$

imp

(Use value of R in accordance to unit of $\Delta H_{vap}$ )

- wherein

$T_{b} =$ Boiling point of pure solvent in gm

$M =$ Molar mass of solvent in gm

$\Delta H_{vap}$ = Enthalpy of vap

R = Universal gas constant

We know Ebullioscopic Contant, $K_a=\frac{RT^2_\mu M}{1000\Delta H_{vap}}$

Where M= molar mass of solvent in gm

$K_a=\frac{JK^{-1}mol^{-1}\times K^2\times Kg}{J}$

K Kg mol^-1 or K(molality)^-1

Option 1)

K Kg mol^-1 or K(molality)^-1

Correct

Option 2)

mol Kg K^-1 or K^-1 (molality)

Incorrect

Option 3)

Kg mol^-1 K^-1 or K^-1(molality)^-1

Incorrect

Option 4)

K Mol Kg^-1or K (molality)

Incorrect

Posted by

Vakul

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