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  • Need explanation for: The unit of Ebulioscopic Contant is

The unit of Ebulioscopic Contant is  

  • Option 1)

    K Kg mol-1 or K(molality)-1

  • Option 2)

    mol Kg K-1  or K-1 (molality)

  • Option 3)

    Kg mol-1 K-1  or K-1 (molality)-1

  • Option 4)

    K Mol Kg-1 or K (molality)

 

Answers (1)

 

Dependence of K_{b} -

K_{b}  depends only on nature of solvent.

K_{b} =\frac{ RT_{b}^{2}\cdot M}{1000\, \Delta H_{vop}}

imp

(Use value of R in accordance to unit of \Delta H_{vap})
 

 

- wherein

T_{b} = Boiling point of pure solvent in gm

    M = Molar mass of solvent in gm

\Delta H_{vap}= Enthalpy of vap

R = Universal gas constant

 

 We know Ebullioscopic Contant, K_a=\frac{RT^2_\mu M}{1000\Delta H_{vap}}

Where M= molar mass of solvent in gm

K_a=\frac{JK^{-1}mol^{-1}\times K^2\times Kg}{J}

K Kg mol-1 or K(molality)-1


Option 1)

K Kg mol-1 or K(molality)-1

Correct

Option 2)

mol Kg K-1  or K-1 (molality)

Incorrect

Option 3)

Kg mol-1 K-1  or K-1 (molality)-1

Incorrect

Option 4)

K Mol Kg-1 or K (molality)

Incorrect

Posted by

Vakul

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