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Negation of the statement p: for every real number, either x > 1 or x < 1 is

Option: 1

 There exist a real number x such that neither x > 1 nor x < 1

        


Option: 2

 

  There exist a real number x such that 0 < x < 1

     


Option: 3

 

 There exist a real number x such that neither x ³ 1 nor x \leq1


Option: 4

none 


Answers (1)

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As we have learnt in

 

Negation of Disjunction "OR" -

\sim (p\vee q)=\sim p\wedge \sim q

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Negation of p \vee q \: \: is \: \: (\sim p ) \wedge ( \sim q )

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