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Nessler’s reagent on reacting with \mathrm{NH_3} in presence of \mathrm{KOH} gives a brown precipitate. What is the brown precipitate?

Option: 1

\mathrm{HgO.Hg(NH_2)I}
 


Option: 2

\mathrm{Hg_2(NH_2)_2}
 


Option: 3

\mathrm{HgO.Hg(NH_2)Cl}

 


Option: 4

\mathrm{Hg(NH_2)I}


Answers (1)

best_answer

On passing the gas through Nessler’s reagent, a brown colouration or a precipitate of basic mercury(II) amido-iodine is formed.

\mathrm{2K_2HgI_4 + NH_3 + 3KOH \rightarrow HgO.Hg(NH_2)I (Brown Ppt.) + 7KI + 2H_2O}

Hence option 1 is correct.

 

Posted by

manish painkra

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