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A 10kg block kept on an inclined plane is pulled by a string applying 200N force. A 10 force is also applied on 10kg block as shown in figure. find the net force on pulley exerted by the string?

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\\\text{Tension in the string }"T" = 200 N \\ \text{Let acceleration be }"a" $"$ \\ 200-10-100 \sin 30=10 a \\ a=140 / 10 \\ a=14 \mathrm{m} / \mathrm{s}^{\wedge} 2\\ \text{Net force on pulley }$=\sqrt{(} 200)^{\wedge} 2+(200)^{\wedge} 2$ =200 \sqrt{2} \mathrm{N}\\ \text{Thus the tension in the string is }$200 \sqrt{2} \mathrm{N}$.

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