# A 10kg block kept on an inclined plane is pulled by a string applying 200N force. A 10 force is also applied on 10kg block as shown in figure. find the net force on pulley exerted by the string?

$\\\text{Tension in the string }"T" = 200 N \\ \text{Let acceleration be }"a" " \\ 200-10-100 \sin 30=10 a \\ a=140 / 10 \\ a=14 \mathrm{m} / \mathrm{s}^{\wedge} 2\\ \text{Net force on pulley }=\sqrt{(} 200)^{\wedge} 2+(200)^{\wedge} 2 =200 \sqrt{2} \mathrm{N}\\ \text{Thus the tension in the string is }200 \sqrt{2} \mathrm{N}.$

### Preparation Products

##### JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
##### Knockout JEE Main April 2021 (Subscription)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 6999/- ₹ 5/-
##### Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
##### Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-