Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Normals AO, AA1, AA2 are drawn to parabola y2 = 8x from the point A (h, 0) . If triangle OA1A2 (O being the origin) is equilateral, then possi

Normals AO, AA1, AA2 are drawn to parabola y2 = 8x from the point A (h, 0) . If triangle OA1A2 (O being the origin) is equilateral, then possible value of ‘h’ is

Option: 1

26


Option: 2

24


Option: 3

28


Option: 4

22


Answers (1)

best_answer

 

Standard equation of parabola -

y^{2}=4ax

- wherein

 

 

\therefore OA_{1} A_{2} is equilateral traingle

\therefore \angle A_{1}OA=\frac{\pi}{6}

\Rightarrow Slope \; OA_{1}=\frac{1}{\sqrt{3}}

 

\Rightarrow \frac{2}{t_{1}}=\frac{1}{\sqrt{3}}\Rightarrow t_{1}=2\sqrt{3}.

\therefore equation of normal at A1 is y=-t_{1}x+4t_{1}+2t_{1}^{3}

\therefore it passes through A(h,0)

\Rightarrow h=4+2t_{1}^{2}                                  \Rightarrow h=4+2\times4\times3=28

\therefore Coordinates of the point R are \left ( \frac{1}{4},1 \right )

Posted by

chirag

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JAC Chandigarh Counselling 2025: Round 1 seat allotment result out for BTech admissions
anam-khan

JoSAA round 5 seat allotment result 2025 out on josaa.nic.in
anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today

Latest Question