Number of atoms in 558.5 gram Fe (at. wt.of Fe = 55.85 g mol-1) is:

Answers (1)

 Number of moles of Fe atom \mathrm{=\frac{558.5}{55.85}=10\ mole}

Total number of atom =10\times 6.022\times 10^{23}=6.022 \times10^{24}

12 g of carbon means Avogadro's number,

Therefore, 60 g of carbon means 5 moles of carbon

Thus contains 5XNatoms, twice of this equals 10Natoms of carbon.

Total number of atom =10\times 6.022\times 10^{23}=6.022 \times10^{24}

6.022 \times10^{24} no. of atoms found in twice that in 60 g carbon.

Ans. Option (1)


Option 1)

twice that in 60 g carbon

This is correct option.

Option 2)

6.023 × 1022

This is an incorrect option.

Option 3)

half that in 8 g He

This is an incorrect option.

Option 4)

558.5 × 6.023 × 1023

This is an incorrect option.

Preparation Products

Knockout JEE Main April 2021 (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 14000/- ₹ 4999/-
Buy Now
Knockout JEE Main May 2021

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 22999/- ₹ 9999/-
Buy Now
Test Series JEE Main May 2021

Unlimited Chapter Wise Tests, Unlimited Subject Wise Tests, Unlimited Full Mock Tests, Get Personalized Performance Analysis Report,.

₹ 6999/- ₹ 2999/-
Buy Now
Knockout JEE Main May 2022

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 34999/- ₹ 14999/-
Buy Now
JEE Main Rank Booster 2021

Booster and Kadha Video Lectures, Unlimited Full Mock Test, Adaptive Time Table, 24x7 Doubt Chat Support,.

₹ 13999/- ₹ 6999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions