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  • of a hydrocarbon <img alt="(M.F. \mathrm{C}_{10} \mathrm{H}_{16} )" src="https://entrancecorner.oncodecogs.com/gif

17mg of a hydrocarbon (M.F. \mathrm{C}_{10} \mathrm{H}_{16} ) takes up 8.40 mL of the H_{2}  gas measured at 0^{\circ}C and 760 mm of Hg. Ozonolysis of the same hydrocarbon yields

The number of double bond/s present in the hydrocarbon is_______

Option: 1

3


Option: 2

"__"


Option: 3

"__"


Option: 4

"__"


Answers (1)

best_answer

Moles of hydrocarbon  =\frac{17 \times 10^{-3}}{136}=1.25 \times 10^{-4}

                        \begin{aligned} & \mathrm{nH}_2=1 \times \frac{8.4}{1000}=\mathrm{n} \times 0.0821 \times 273 \\\ & \Rightarrow \mathrm{n}=3.75 \times 10^{-4}\end{aligned}

Hydrogen molecule used for 1 molecule of hydrogen is 3

                                =\frac{3.75 \times 10^{-4}}{1.25 \times 10^{-4}}=3

Posted by

SANGALDEEP SINGH

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