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Of the following which relation is true?

Option: 1

\beta>\alpha


Option: 2

\alpha>\beta


Option: 3

\alpha \beta=1


Option: 4

\alpha=\beta


Answers (1)

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\mathrm{\alpha \, \, and \, \, \beta }-parameters of a transistor are defined as
\mathrm{\begin{array}{ll} \alpha=\frac{\mathrm{i}_{\mathrm{C}}}{\mathrm{i}_{\mathrm{E}}} \text { and } \beta=\frac{\mathrm{i}_{\mathrm{C}}}{\mathrm{i}_{\mathrm{B}}} \\ \text { where } & i_C=\text { collector current, } \\ & i_E=\text { emitter current, } \\ & i_B=\text { base current } \end{array} }

As \mathrm{i_B } is about 1 to 5% of \mathrm{i_E }, \mathrm{\alpha } is about 0.95 to 0.99 and

\mathrm{\beta\left(\frac{\alpha}{1-\alpha}\right. }, bysimple mathematics ) is about 20 to 100 , we conclude that \mathrm{\beta>\alpha. }

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