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  • On complete combustion of of an organic compound containing <img alt="\mathrm{C}, \

On complete combustion of 0.492 \mathrm{~g} of an organic compound containing \mathrm{C}, \mathrm{H}$ and $\mathrm{O}$, $0.7938 \mathrm{~g}$ of $\mathrm{CO}_{2}$ and $0.4428 \mathrm{~g}$ of $\mathrm{H}_{2} \mathrm{O} was produced. The % composition of oxygen in the compound is_____________.

Option: 1

46


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Given, 
Organic compound containing \mathrm{C,H,O= 0.492\, g.}

\mathrm{CO_{2}\, produced= 0.7938\, g}
\mathrm{H_{2}O\, produced= 0.4428\, g}

Let the organic compound we have us \mathrm{C_{x}H_{y}O_{z}}.

no.of moles of \mathrm{CO_{2}\, in\: 0.7938\, g= 0.018\: moles}
no.of moles of  \mathrm{H_{2}O\, in\: 0.4428\, g= 0.0246\: moles}.

So moles of \mathrm{C= 0.018} which is equal to \mathrm{ 0.216\, g}
moles of \mathrm{ H}   \mathrm{ = 0.0492} which is equal to \mathrm{ 0.0492 \, g}

weight of oxygen = Total weight - weight of C - weight of H
                            \mathrm{ = 0.492-0.216-0.049}
                            \mathrm{ = 0.227\, g.}
\mathrm{ %\, of\, oxygen\: in\: compound= \frac{0.227}{0.492}\times 100%}
                                                        \mathrm{ \cong 46 %\, approx}

Hence answer is 46. 
                                                        
 
 

Posted by

Divya Prakash Singh

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