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\mathrm{ZnCl_2} on reaction with potassium ferrocyanide and ammonium hydroxide gives a bluish white precipitate. What is the compound formed?

Option: 1

\mathrm{ZnFeCN}


Option: 2

\mathrm{Zn_2FeCN_2}


Option: 3

\mathrm{Zn(CN)_2}


Option: 4

\mathrm{Zn_2[Fe(CN)_6]}


Answers (1)

best_answer

When potassium ferrocyanide \mathrm{ K_4Fe(CN)_6} solution is added to the solution after neutralization by \mathrm{NH_4OH} solution, a white or a bluish white precipitate of zinc ferrocyanide appears.

\mathrm{2 ZnCl_2 + K_4 [Fe(CN)_6] \rightarrow Zn_2 [Fe(CN)_6] + 4 KCl}

Hence option 4 is correct.

 

Posted by

shivangi.bhatnagar

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