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One end of a uniform wire of length L and weight W is attached rigidly to a point in roof and a weight  W_1 is suspended from its lower end. If S is the area of cross-section of the wire, the stress in the wire at a height of \frac{3 L}{4} from its lower end is

Option: 1

\frac{W_1}{S}


Option: 2

\frac{W_1+\frac{W}{4}}{S}


Option: 3

\frac{W_1+\frac{3 W}{4}}{S}


Option: 4

\frac{W_1+W}{S}


Answers (1)

best_answer

At length \frac{3 L}{4} from lower end, tension in the wire.

T = Suspended load + \frac{3}{4} \times \text { weight of wire }

T=W_1+\frac{3 W}{4}

\therefore \text { stress }=\frac{T}{S}=\frac{W_1+\frac{3 W}{4}}{S}

 

Posted by

Rakesh

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