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  • One litre of a mixture of CO and CO2 is passed through red hot charcoal in tube. T

One litre of a mixture of CO and CO2 is passed through red hot charcoal in tube. The new volume becomes 1.4 litre, find out % composition of mixture by volume. All measurements are made at same P and T.

Option: 1

CO2 = 50% and CO = 50%


Option: 2

CO2 = 45% and CO = 55%


Option: 3

CO2 = 40% and CO = 60%


Option: 4

CO2 = 60% and CO = 40%


Answers (1)

best_answer

\mathrm{C+C O_{2} \rightarrow 2 C O}

Initial volume =1L

Final volume =1.4L

Let \mathrm{V_{CO_2}=x \quad and \quad V_{CO}=(1-x)}

\begin{array}{l} (1-x)+2 x=1.4 \\ 1+x=1.4 \\ x=0.4 \end{array}

\mathrm{\therefore \% C O_{2}=40 \%, \% C O=60 \%}

Therefore, Option(3) is correct.

Posted by

Devendra Khairwa

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