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  • Only of the optical source frequency is the available channel bandwidth for an optical communicating system operating at <img alt="1000 \mathrm{~nm

Only 2 \% of the optical source frequency is the available channel bandwidth for an optical communicating system operating at 1000 \mathrm{~nm}. If an audio signal requires a bandwidth of 8 \mathrm{kHz}, how many channels can be accommodated for transmission :

 

Option: 1

375 \times 10^{7}


Option: 2

75 \times 10^{7}


Option: 3

375 \times 10^{8}


Option: 4

75 \times 10^{9}


Answers (1)

best_answer

\mathrm{f=\frac{v}{\lambda}=\frac{3 \times 10^{8}}{1000 \times 10^{-9}}=3 \times 10^{14} \mathrm{~Hz}}

No of Channels,

\mathrm{=\frac{\frac{2}{100} \times 3 \times 10^{14}}{8 \times 10^{3}}}

\mathrm{=75\times10^{7}}

Hence, correct answer is Option (2).

 

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Sayak

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