Open pipe of length 33cm resonates to a frequency of 1000hz. The mode of vibration(velocity of sound is 330m/s?

Answers (1)

In open pipe, the frequency is given as  v  = v/2L  ⇒ 330/33 x 10-2 x 2 = 500 Hz. Since, frequency (1000) is double of fundamental frequency (500) . Hence, second harmonic take place.

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