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Out of the given options, which one are the Lewis acid

\mathrm{CCl_4,SiCl_4,SnCl_4}

Option: 1

\mathrm{CCl}_4

 


Option: 2

\mathrm{SiCl}_4
 


Option: 3

\mathrm{SiCl}_4, \mathrm{SnCl}_4
 


Option: 4

\mathrm{CCl}_4, \mathrm{SnCl}_4


Answers (1)

best_answer

\mathrm{SiCl}_4 \: \&\: \mathrm{SnCl}_4 silly are hydrolysed to form acidic solution as well as they can act as lewis acid because they can increase their co-ordination number grater than 4 due to availability of d-orbitals.

\mathrm{ \mathrm{SiCl}_4+4 \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{Si(OH)}_4+4 \mathrm{HCl} }

\mathrm{ \mathrm{SnCl}_4+4 \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{Sn}(\mathrm{OH})_4+4 \mathrm{HCl} }

\mathrm{ \mathrm{SiCl}_4+2 \mathrm{Cl}^{-} \rightarrow\left[\mathrm{SiCl}_6\right]^{2-} }

Hence option 3 is correct.




 

Posted by

Ritika Harsh

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