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Oxidation of succinate ion produces ethylene and carbondioride gases. On passing 0.15 Faraday electricity through an aqueous solution of potassium succinate, what is the total volume of gases (at both anode & cathode) at STP (1 atm & 273k)?

Option: 1

1.37 L


Option: 2

2.26 L


Option: 3

3.84 L


Option: 4

6.72 L
 


Answers (1)

best_answer

Ethane, \mathrm{CO_2} , \mathrm{H_2O}  are gases
So total moles of gas =1+2+1
                                   =4
By 2 Faraday = 4 Moles of gas produced
So by   \mathrm{ 0.5=\frac{4}{2} \times 0.15}
                   =0.3  mole gas produced
\mathrm{ V=\frac{n R T}{P}=\frac{0.3 \times 0.0821 \times 273}{1}}.

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Divya Prakash Singh

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