pendulum of length 1 m is released from \theta = 60\degree. the rate of chage of speed of bob at \theta = 30\degree is

Answers (1)

Rate of change of speed

\frac{d v}{d t}$  =tangential acceleration

=\frac{\tan g e n t i a l \text { force }}{\text {mass}} \\ \\ =\frac{m g \sin 30^{\circ}}{m}

=10\left(\frac{1}{2}\right) m / s^{2}=5 m / s^{2}

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