When an source of e.m.f, e =   is connected across a circuit, the phase difference between the e.m.f. e and the current I in the circuit is observed to be , as shown in the diagram. If the circuit consists possibly only of RC or LC or LR in series, find the relationship between the two elements

Answers (1)

As the current i leads the voltage by π/4 it is an RC circuit, hence

\begin{array}{l} \tan \phi=\frac{X_{C}}{R} \Rightarrow \tan \frac{\pi}{4}=\frac{1}{\omega C R} \\ \\ \Rightarrow \omega C R=1 \text { as } \omega=100 \mathrm{rad} / \mathrm{sec} \\ \\ \Rightarrow C R=\frac{1}{100} \sec ^{-1} \end{array}

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