Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

Answers (1)

given x = at2 - bt3            ......(1)

velocity = \frac{dx}{dt} = 2at- 3bt2

Displacement of the particle when velocity = 0 

0 =  2at- 3bt2 

t = \frac{2a}{3b}      ( substitute the value of t is eq. 1)  

x when velocity = 0 would be, 

x = \frac{4a^3}{27b^2}

 

Posted by

Satyajeet Kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question