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header-bg qa

The spring constant from the adjoining
combination of springs is.

Answers (1)

from fig. 1 lower Spring are in parallel combination.

So, Keq1=K1+K2

\begin{array}{l} k e q 1=k+k \\ k e q 1=2 k \end{array}

spring A and Keq1 are in parallel combination

So, Keq2= KA+Keq1

\begin{array}{l} k e q 2=2 k+2 k \\ k e q 2=4 k \end{array}

So the required answer is 4K.

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