Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Please help! A 3.0 kg object is moving to the right at 4.0 m/s. It collides in a perfectly inelastic collision with a 6.0 kg object moving to the left at 2.0 m/s. What is the total kinetic energy after the collision?

A 3.0 kg object is moving to the right at 4.0 m/s. It collides in a perfectly inelastic collision with a 6.0 kg object moving to the left at 2.0 m/s. What is the total kinetic energy after the collision?

  • Option 1)

    62 J

  • Option 2)

    25 J

  • Option 3)

    12 J

  • Option 4)

    0.0 J

 

Answers (1)

best_answer

As we discussed in concept

Perfectly Inelastic Collision -

v= \frac{m_{1}v_{1}+m_{2}v_{2}}{m_{1}+m_{2}}

- wherein

Two bodies stick together after the collision ,so there will be a final common velocity (v)

m_{1},m_{2}= masses

v_{1}=\: initial \: velocity \: mass\: m_{1}

v_{2}=\: initial \: velocity \: mass\: m_{2}

 

 m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})V

V=\frac{m_{1}v_{1}+m_{2}v_{2}}{m_{1}+m_{2}}=\frac{12+12}{9}=\frac{24}{9}=\frac{8}{3}\:ms^{-1}

    K=\frac{1}{2}(m_{1}+m_{2})V^{2}=\frac{1}{2}.\:9\times (\frac{8}{3})^{2}

K=\frac{1}{2}.\:9\times \frac{64}{9}\:=\:32J


Option 1)

62 J

This option is incorrect.

Option 2)

25 J

This option is incorrect.

Option 3)

12 J

This option is incorrect.

Option 4)

0.0 J

This option is incorrect.

Posted by

Plabita

View full answer

Similar Questions

Trending Articles/News

anam-khan

BITSAT iteration 1 result 2025 out on bitsadmission.com; confirm allotment by July 14
anam-khan

BITSAT 2025 preference editing window open till July 5 for BE, BPharm, MSc admission
anam-khan

BITSAT cut-off for BE Computer Science slightly drops, increases for all others; session 2 result soon

Latest Question