A wire of length L metre carrying a current of I ampere is bent in the form of a circle. Its magnitude of magnetic moment will be

 

  • Option 1)

    \frac{IL}{4\pi}

     

  • Option 2)

    \frac{IL^{2}}{4\pi}

  • Option 3)


    \frac{I^{2}L^{2}}{4\pi}

  • Option 4)

    \frac{I^{2}L}{4\pi}

 

Answers (1)

As we learnt in 

Magnetic moment (M) -

M=NiA

- wherein

N-number of turns in the coil 

i-current throughout the coil 

A-area of the coil 

 

 Magnetic moment \vec{\mu }=I\vec{A}

=I.\pi r^{2}=I.\pi(\frac{L}{2\pi})^{2}

=\frac{IL^{2}}{4\pi}


Option 1)

\frac{IL}{4\pi}

 

incorrect 

Option 2)

\frac{IL^{2}}{4\pi}

correct 

Option 3)


\frac{I^{2}L^{2}}{4\pi}

incorrect 

Option 4)

\frac{I^{2}L}{4\pi}

incorrect 

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