Consider an electron in a hydrogen atom, revolving in its second excited state (having radius 4.65\AA). The de-Broglie wavelength of this electron is:

 

  • Option 1)

    3.5 \AA

  • Option 2)

    6.6 \AA

  • Option 3)

    12.9 \AA

     

  • Option 4)

    9.7 \AA

 

Answers (1)

2\pi r_{n}=n\lambda _{n}

\lambda _{3}=\frac{2\pi (4.65\times 10^{-10})}{3}

\lambda _{3}=9.7\AA


Option 1)

3.5 \AA

Option 2)

6.6 \AA

Option 3)

12.9 \AA

 

Option 4)

9.7 \AA

Preparation Products

Knockout JEE Main April 2021 (One Month)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 14000/- ₹ 6999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Test Series JEE Main April 2021

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 6999/- ₹ 4999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions