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Consider an electron in a hydrogen atom, revolving in its second excited state (having radius $4.65\AA$ ). The de-Broglie wavelength of this electron is:

Option 1)
3.5 $\AA$

Option 2)
6.6 $\AA$

Option 3)
12.9 $\AA$

Option 4)
9.7 $\AA$

Answers (1)

S solutionqc

$2\pi r_{n}=n\lambda _{n}$

$\lambda _{3}=\frac{2\pi (4.65\times 10^{-10})}{3}$

$\lambda _{3}=9.7\AA$

Option 1)

3.5 $\AA$

Option 2)

6.6 $\AA$

Option 3)

12.9 $\AA$

Option 4)

9.7 $\AA$

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