# Equation of the tangent to the circle, at the point (1, −1), whose centre is the point of intersection of the straight lines x − y = 1 and 2x + y = 3 is : Option 1) 4x  + y − 3 = 0 Option 2) x + 4y + 3 = 0 Option 3) 3x − y − 4 = 0 Option 4)  x − 3y − 4 = 0

As we learnt in

Condition for perpendicular lines -

- wherein

Here   are the slope of perpendicular lines.

Centre of  circle is

slpoe of OP =

Since tangent and radius are perpendicular

So slope of tangent will be

equation

Option 1)

4x  + y − 3 = 0

Incorrect

Option 2)

x + 4y + 3 = 0

Correct

Option 3)

3x − y − 4 = 0

Incorrect

Option 4)

x − 3y − 4 = 0

Incorrect

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