Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Please help! If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n = 2 is

If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n = 2 is

  • Option 1)

    10.2 eV

  • Option 2)

    0 eV

  • Option 3)

    3.4 eV

  • Option 4)

    6.8 eV

 

Answers (1)

best_answer

As we learnt in

Ionization energy -

E_{ion }= E_{\infty }-E_{n }

=13.6\frac{Z^{2}}{n^{2}}

 

- wherein

Energy required to move an electron from ground state to n= \infty

 

 \Delta E =E_{0}z^{2}\left(\frac{1}{n_{i}^{2}}-\frac{1}{n_{f}^{2}} \right )

For an electron to remove from 

n = 2

ni = 2

n_{f}\rightarrow \infty

E_{0}=13.6\ eV     &    z = 1

\therefore\ \; \Delta E=13.6\left(\frac{1}{4} \right )=3.4\ eV

Correct option is 3.


Option 1)

10.2 eV

This is an incorrect option.

Option 2)

0 eV

This is an incorrect option.

Option 3)

3.4 eV

This is the correct option.

Option 4)

6.8 eV

This is an incorrect option.

Posted by

perimeter

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JoSAA 2024 round 4 seat allotment results out at josaa.nic.in; report online by July 15

Latest Question