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Please help! In bisulphate ion, the formal charge on S atom is

In bisulphate ion, the formal charge on S atom is

  • Option 1)

    +1

  • Option 2)

    +2

  • Option 3)

    +4

  • Option 4)

    +6

 
Answers (1)
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As we learnt in

Formal charge -

Formal charge is difference between the number of valence electron in an isolated atom and number of electrons assigned to that atoms in lewis structure.  

- wherein

Formal Charge = Total number of valence electrons in free atom -\frac{1}{2} (total no. of shared electrons)

 In {HSO_{4}}^{-}  ion, for S, we have

Valence electrons = 6

For structure 2, shared electrons = 8

\therefore Formal charge = 6 -\frac{1}{2}\left ( 8 \right )

                            = 6 -4 = +2

P.S. Formal charge will be different for structure 1 (o) but that is not provided in the options.


Option 1)

+1

This option is incorrect

Option 2)

+2

This option is correct

Option 3)

+4

This option is incorrect

Option 4)

+6

This option is incorrect

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