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  • Please help! In ZnS crystal , S2- occupy all corners and face centres while Zn2+ occupy alternate tetrahedral voids. If sum of radius of Zn2+ and S2- ion is 280 pm then the edge length of unit cell is

In ZnS crystal , S2- occupy all corners and face centres while Zn2+ occupy alternate tetrahedral voids. If sum of radius of Zn2+ and S2- ion is 280 pm then the edge length of unit cell is

  • Option 1)

    342.8 pm

  • Option 2)

    646.6 pm

  • Option 3)

    280 pm

  • Option 4)

    121.2 pm

 

Answers (2)

Edge\; length=\frac{4}{\sqrt{3}}\left ( r_{Zm^{2+}} +r_{s^{2-}}\right )

                            =\frac{4}{\sqrt{3}}\left ( 280 \right )=646.6pm

 

 

Zinc blende structure (ZnS) -

{S^{2-} arrange in CCP

 

{Zn^{2+} found in 50% tetrahedral voids

 

Edge length = \frac{4}{\sqrt{3}} (r_{Zn^{2+}} + r_{S^{2-}})

 

Coordination number = 4:4

- wherein

Number or {S^{2-} = 4

Number of {Zn^{2+} = 4

Number of ZnS molecule per unit cell = 4

Example = AgCl , AgBr , CuCl , CuBr , etc

 

 


Option 1)

342.8 pm

This is incorrect

Option 2)

646.6 pm

This is correct

Option 3)

280 pm

This is incorrect

Option 4)

121.2 pm

This is incorrect

Posted by

subam

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