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  • Please help! - is 40 % ionised in aqueous solution. The value of its van't Hoff factor (i) is : - Solutions - JEE Main

K_{2}HgI_{4} is 40 % ionised in aqueous solution. 

The value of its van't Hoff factor (i) is :

  • Option 1)

    2.2

  • Option 2)

    1.8

  • Option 3)

    2.0

  • Option 4)

    1.6

Answers (1)

best_answer

 

Vant Hoff factor (i) -

In case of electrolytes the observed colligative property is different from theoritical colligative property. There ratio is defined by Vant Haff factor

- wherein

i = \frac{observed}{theoritical}

K_{2}[HgI_{4}]\rightarrow 2K^{+}+[HgI_{4}]^{2-}\: \: \: ;n=3

i = 1+3(3-1)\times 0.4

i = 1+2\times 0.4=1.8=1.8

 

 

 

Vant Hoff factor for dissociation -

i= 1+(n-1)\alpha

Where

n is the no. of dissociated particles

\alpha = degree of dissociation
 

- wherein

NaC l \: \: \: n = 2

CaCl_{2} \: \: \: n = 3

K_{4}[F(CN_{6})]\: \: \: \: \: n=5

 

 

 

Vant Hoff factor for Association -

i=1-\alpha +\frac{\alpha }{n}

n= number of particles associated

\alpha = degree of association

e.g. Carboxylic acid dimerized in non polar solvents like Hexane.
 

- wherein

n = 2 for dimerization

n = 3 for trimerization

 

 


Option 1)

2.2

Option 2)

1.8

Option 3)

2.0

Option 4)

1.6

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