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  • Please help! Let C be the circle with centre at (1, 1) and radius = 1. If T is the circle centred at (0, y), passing through origin and touching the circle C externally, then the radius of T is equal to :

 Let C be the circle with centre at (1, 1) and radius = 1. If T is the circle centred at (0, y), passing through origin and touching the circle C externally, then the radius of T is equal to :

  • Option 1)

    \frac{1}{2}\;

  • Option 2)

    \frac{1}{4}

  • Option 3)

    \frac{\sqrt{3}}{\sqrt{2}}

  • Option 4)

    \frac{\sqrt{3}}{2}

 

Answers (2)

best_answer

As we learnt in

Circle touching y-axis and having radius r -

x^{2}+y^{2}+ 2gx\pm 2ry+g^{2}= 0

- wherein

Where g is a variable parameter.

 According to Pythagorus theorem,

(1+y)^{2}\:=\:(1-y)^{2}\:+1

y\:=\:\frac{1}{4}

 


Option 1)

\frac{1}{2}\;

This option is incorrect.

Option 2)

\frac{1}{4}

This option is correct.

Option 3)

\frac{\sqrt{3}}{\sqrt{2}}

This option is incorrect.

Option 4)

\frac{\sqrt{3}}{2}

This option is incorrect.

Posted by

Aadil

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