Consider the following linear programming problem

Maximize  5x+6y

Subject to 4x+2y\leq420,         1x+2y\leq120

all variables \geq 0

which of the following points (x,y) is feasible?

  • Option 1)

    (50,40)

  • Option 2)

    (30,50)

  • Option 3)

    (60,30)

  • Option 4)

    (90,20)

 

Answers (1)

As we learnt in 

Decision Variables -

In Z = ax+by, x and y are decision variables. 

-

 

 Z=5x+6y

 4x+2y\leq420         

x+2y\leq120

x = 60

y = 30 is feasible.


Option 1)

(50,40)

Incorrect

Option 2)

(30,50)

Incorrect

Option 3)

(60,30)

correct

Option 4)

(90,20)

Incorrect

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