a bullet of mass 10g travels horizontally with a speed of 100m/s and is absorbed by a wooden block of mass 990g suspended by a string. Find the vertical height through which the block rises
The mass of the bullet,m1 =10g = 0.010 kg
Mass of the block. m2 =990g =0.990kg
Initial velocity of the bullet, u1 =100 m/s
Initial velocity of the block, u2 = 0
Let v be the velocity acquired by the block and bullet together after collision.
Then according to the principle of conservation of momentum:
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