A thin smooth rod of length L and mass M is rotating freely with angular speed $\omega _{0}$ about an axis perpendicular to the rod and passing through its centre . Two beads of mass m and negligible size are at the centre of the rod initially. The beads are free to slide along the rod . The angular speed of the system , when the beads reach the opposite ends of the rod will be :

Option 1)
$\frac{M\:\omega _{0}}{M+m}$

Option 2)
$\frac{M\:\omega _{0}}{M+3m}$

Option 3)
$\frac{M\:\omega _{0}}{M+6m}$

Option 4)
$\frac{M\:\omega _{0}}{M+2m}$

Answers (1)

S solutionqc

Applying conservation of angular momentum

$\left ( \frac{ML^{2}}{12} \right )\omega_{0}=\left [ \frac{ML^{2}}{12}+2m\left ( \frac{L}{2} \right )^{2} \right ]\omega^{1}$

$\Rightarrow ML^{2}\omega _{0}=\left ( ML^{2}+6mL^{2} \right )\omega ^{1}$

$\Rightarrow \omega^{1}=\frac{\omega_{0}M}{M+6m}$

Option 1)

$\frac{M\:\omega _{0}}{M+m}$

Option 2)

$\frac{M\:\omega _{0}}{M+3m}$

Option 3)

$\frac{M\:\omega _{0}}{M+6m}$

Option 4)

$\frac{M\:\omega _{0}}{M+2m}$

Exams

Colleges

Predictors

Resources

Quick links

Exams

Colleges

Resources

Colleges

Resources

Exams

Exams

Colleges

Predictor

Resources

Exams

Predictors

Resources

Upcoming Events

Exams

Ranking

Products & Resources

NCERT Solutions

Exams

Resources

Exams

Colleges

Predictors

Resources

Exams

Colleges

Predictors

Resources

Online Courses

Products

Engineering Preparation

Medical Preparation

Exams

Colleges

Predictors

Resources

Resources

Exams

Colleges

Predictors

Exams

Predictors

Colleges

Resources

Exams

Colleges

Resources

Exams

Resources

Similar Questions

Preparation Products

Knockout JEE Main April 2021 (One Month)

Knockout JEE Main April 2021

Test Series JEE Main April 2021

Knockout JEE Main April 2022

JEE Main Rank Booster 2021

Ask Question

Welcome Back :)

Register to post Answer

Welcome Back :)