# The distance of the point (1, −2, 4) from the plane passing through the point (1, 2, 2) and perpendicular to the planes x − y + 2z = 3 and  2x −2y + z + 12=0, is : Option 1) Option 2) Option 3) Option 4)

As we learnt in

Distance of a point from plane (Cartesian form) -

The length of perpendicular from to the plane

is given by

-

Normal vector of plane is

So equation of plane is

passes through (1,2,2)

3+6=C

3x+3y=9    =>    x+y=3

Distance

Option 1)

This option is correct

Option 2)

This option is incorrect

Option 3)

This option is incorrect

Option 4)

This option is incorrect

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