The mole fraction of ethylene glycol (C2H6O2) in an aqueous solution containing 10% of C2H6O2 by mass

  • Option 1)

    0.932

  • Option 2)

    0.322

  • Option 3)

    0.068

  • Option 4)

    0.0312

 

Answers (1)

As we learned in concept

Mole Fraction -

\dpi{100} Mole\: Fraction= \frac{Moles\: o\! f\: solute}{Moles\: o\! f solute+Moles\: o\! f solvent}

-

 

 molar mass of  ethylene glycol (C2H6O2)=62

100g of solution containing 10g of  C2H6O2  and 90g H2O.

moles\ of\ C_2H_6O_2 = \frac{10}{62}=0.161

moles\ of\ H_{2}O=\frac{90}{18}=5

Mole fraction of  ethylene glycol =\frac{0.161}{0.16145}

= 0.0312

 


Option 1)

0.932

Option is incorrect

Option 2)

0.322

Option is incorrect

Option 3)

0.068

Option is incorrect

Option 4)

0.0312

Option is correct

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