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Please help! - Thermodynamics - JEE Main

If C_{P} and C_{V} denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then

  • Option 1)

    C_{P}-C_{V}=28/R

  • Option 2)

    C_{P}-C_{V}=R/28

  • Option 3)

    C_{P}-C_{V}=R/14

  • Option 4)

    C_{P}-C_{V}=R

 
Answers (1)
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As we learnt in 

Specific heat in isobaric process -

C_{p}= \left ( \frac{f}{2}+1 \right )R

\gamma^{mix}=\frac{n_{1}C_{p1}+n_{2}C_{p2}}{n_{1}C_{v1}+n_{2}C_{v2}}

 

- wherein

f is degree of freedom

 

 Difference between moler specific heat = R

C_{p}\:-C_{v}\:=R

1 mole = 28g of nitrogen.

\therefore \:C_{p}\:-C_{v}\:=\frac{R}{28}

where C_{p} & C_{v} denote specific heats of nitrogen per unit mass.


Option 1)

C_{P}-C_{V}=28/R

This option is incorrect.

Option 2)

C_{P}-C_{V}=R/28

This option is correct.

Option 3)

C_{P}-C_{V}=R/14

This option is incorrect.

Option 4)

C_{P}-C_{V}=R

This option is incorrect.

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