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A rod of length 2m is suspended  through an end and is set into oscialltions with small Amplitudes under gravity. The time period of the oscillation is

  • Option 1)

    1.60 s

  • Option 2)

    1.80 s

  • Option 3)

    2 s

  • Option 4)

    2.40 s

 

Answers (1)

best_answer

T = 2\pi\sqrt{\frac{2l}{3g}}\;\;\;\left[Physical \;Pendulum \right ] \\* \Rightarrow T = 2\pi\sqrt{\frac{2\times 2}{3 \times 9.8}} = 2.4 s

 

Physical pendulum -

Any rigid body suspended from a fixed support constitute a physical pendulum.

- wherein

e.g.

A circular ring suspended on a nail in a wall etc.

 

 

 


Option 1)

1.60 s

This is incorrect.

Option 2)

1.80 s

This is incorrect.

Option 3)

2 s

This is incorrect.

Option 4)

2.40 s

This is correct.

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prateek

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