The above is a plot of binding energy per nucleon E_{b}, against the nuclear mass M; A,B,C,D,E,F correspond to different nuclei. Consider four reactions:

(i)\; \; A+B\rightarrow C+\varepsilon              (ii)\; \; C\rightarrow A+B+\varepsilon

(iii)\; \; D+E\rightarrow F+\varepsilon           (iv)\; \; F\rightarrow D+E+\varepsilon

where \varepsilon is the energy released? In which reactions is \varepsilon positive?

  • Option 1)

    (i)\; \; and\; \; (iv)

  • Option 2)

    (i)\; \; and\; \; (iii)

  • Option 3)

    (ii)\; \; and\; \; (iv)

  • Option 4)

    (ii)\; \; and\; \; (iii)

 

Answers (1)

As we learnt in

Binding energy per nucleon -

 

- wherein

This graph shows the stability of nuclei many nuclear phenomena can be explained by this graph

 

 Energy is released when the product is more stable than the reactant.

In option (i) , product c is more stable than A & B hence \epsilon is positive.

In option (ii), product is less stable hence \epsilon is negative.

In option (iii), product is less stable hence \epsilon is negative.

In option (iv), F is less stable than D + E and hence energy will releases. So \epsilon is positive.

Correct option is 1.


Option 1)

(i)\; \; and\; \; (iv)

This is the correct option.

Option 2)

(i)\; \; and\; \; (iii)

This is an incorrect option.

Option 3)

(ii)\; \; and\; \; (iv)

This is an incorrect option.

Option 4)

(ii)\; \; and\; \; (iii)

This is an incorrect option.

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