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Q

The above is a plot of binding energy per nucleon $\dpi{100} E_{b},$ against the nuclear mass $\dpi{100} M;$ $\dpi{100} A,B,C,D,E,F$ correspond to different nuclei. Consider four reactions:

$\dpi{100} (i)\; \; A+B\rightarrow C+\varepsilon$              $\dpi{100} (ii)\; \; C\rightarrow A+B+\varepsilon$

$\dpi{100} (iii)\; \; D+E\rightarrow F+\varepsilon$           $\dpi{100} (iv)\; \; F\rightarrow D+E+\varepsilon$

where $\dpi{100} \varepsilon$ is the energy released? In which reactions is $\dpi{100} \varepsilon$ positive?

• Option 1)

$(i)\; \; and\; \; (iv)$

• Option 2)

$(i)\; \; and\; \; (iii)$

• Option 3)

$(ii)\; \; and\; \; (iv)$

• Option 4)

$(ii)\; \; and\; \; (iii)$

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As we learnt in

Binding energy per nucleon -

- wherein

This graph shows the stability of nuclei many nuclear phenomena can be explained by this graph

Energy is released when the product is more stable than the reactant.

In option (i) , product c is more stable than A & B hence $\epsilon$ is positive.

In option (ii), product is less stable hence $\epsilon$ is negative.

In option (iii), product is less stable hence $\epsilon$ is negative.

In option (iv), F is less stable than D + E and hence energy will releases. So $\epsilon$ is positive.

Correct option is 1.

Option 1)

$(i)\; \; and\; \; (iv)$

This is the correct option.

Option 2)

$(i)\; \; and\; \; (iii)$

This is an incorrect option.

Option 3)

$(ii)\; \; and\; \; (iv)$

This is an incorrect option.

Option 4)

$(ii)\; \; and\; \; (iii)$

This is an incorrect option.

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