Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Please,please help me - Chemical Kinetics and Surface Chemistry - BITSAT

The rate constant for the reaction, 2N_{2}O_{5}\rightarrow 4NO_{2}+O_{2}\ is\ 3\times 10^{-5} \sec ^{-1} . If the rate  is 2.40\times 10^{-5} mol\left | l \right |\sec, then the concn of N_{2}O_{5} (in mol/l) is

  • Option 1)

    1.4

  • Option 2)

    1.2

  • Option 3)

    0.04

  • Option 4)

    0.8

 

Answers (1)

As we learned in concept

Order of a Reaction -

The order of a reaction is determined as the sum of the powers of the concentration terms that appear in the experimental rate equation. It is an experimental quantity.

- wherein

Formula: aA+bB\rightarrow cC+dD

               r=K[A]^{a}[B]^{b}

              order=(a+b)

  \therefore     Order has relation with stoichiometry & is determined experimentally. It can be zero/fraction/negative/positive

 

 

The reaction given is  2N_2O_5\rightarrow 4NO_2+O_2

Rate constant given is 3*10^{-1}s^{-1}

According to the units of the rate constant , it is clear that the orderof the reaction is 1. 

Rate given = 2.4*10^{-1}mol \: \: l^{-1}s^{-1}

Since, the order of reactionis 1.

Therefore, r= k[N_2O_5]

2.4 * 10^{-5}mol\: \: l^{-1}s^{-1}= 3*10^{-5}s^{-1}[N_2O_5]

[N_2O_5]=0.8 M 


Option 1)

1.4

Incorrect option

Option 2)

1.2

Incorrect option

Option 3)

0.04

Incorrect option

Option 4)

0.8

Correct option

Posted by

Vakul

View full answer

Similar Questions

Latest Question