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Shown in the figure is a shell made of a conductor. It has inner radius a and outer radius b, and carries charge Q, At its centre is a dipole \vec{p} as shown. In  this case :

  • Option 1)

    surface charge density on the outer surface depends on \left|\vec{p} \right |

  • Option 2)

    electric field outside the shell is the same as that of a point charge at the centre of the shell

  • Option 3)

    surface charge density on the inner surface is uniform and equal to \frac{(Q/2)}{4\pi a^{2}}

  • Option 4)

    surface charge density on the inner surface of the shell is zero everywhere 

 

Answers (1)

best_answer

The electric field formed by dipole is non-uniform and hence the charge induced on the inner surface is also non-zero and non-uniform. So far any observed outside the shell, the resultant electric field is due to Q uniformly distributed on outer surface and it is equal to E=\frac{KQ}{r^{2}}


Option 1)

surface charge density on the outer surface depends on \left|\vec{p} \right |

Option 2)

electric field outside the shell is the same as that of a point charge at the centre of the shell

Option 3)

surface charge density on the inner surface is uniform and equal to \frac{(Q/2)}{4\pi a^{2}}

Option 4)

surface charge density on the inner surface of the shell is zero everywhere 

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