In Clark's method, the chemical used to remove hardness of water is

  • Option 1)

    Na_{2}CO_{3}

  • Option 2)

    Ca(OH)_{2}

  • Option 3)

    NaOH

  • Option 4)

    Na_{3}PO_{4}

 

Answers (1)

As we learnt in 

Clark's Method -

In this method temporary hardness is removed by adding Slaked Lime Ca(OH)2

-

 

In Clark's method, temporary hardness is removed by adding Slaked Lime Ca(OH)2. 

Ca (HCO3)2 + Ca (OH)\rightarrow2CaCO+ 2H2O

Mg (HCO3)2 + Ca (OH)\rightarrowCaCO+MgCO+ 2H2O

The carbonates formed are insoluble and are separated by filteration.


Option 1)

Na_{2}CO_{3}

This option is incorrect

Option 2)

Ca(OH)_{2}

This option is correct

Option 3)

NaOH

This option is incorrect

Option 4)

Na_{3}PO_{4}

This option is incorrect

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