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# Engineering

A moving coil galvanometer has a coil with 175 turns and area   1\:\:cm^{2}. It uses a torsion band of torsion constant 10^{-6}\:\:N-m/rad . The coil is placed in a magnetic field B parallel to its plane . The coil deflects by  1^{0} for a current of 1\:\:mA . The value of B ( in Tesla ) is approximately :

  • Option 1)

    10^{-4}

  • Option 2)

    10^{-2}

  • Option 3)

    10^{-1}

  • Option 4)

    10^{-3}

 

Answers (1)
S solutionqc

Given 

N=175

A=1\:\:cm^{2}

\Phi =\frac{\pi}{180}\:rad

I=10^{-3}A

C=10^{-6}N-m

\Rightarrow BINA=C\Phi

B=\frac{C\Phi}{INA}

B=\frac{10^{-6}}{10^{-3}\times 175 \times 10^{-4}}\times \frac{\pi}{180}=0.0010

B=10^{-3}\:\:Tesla

 


Option 1)

10^{-4}

Option 2)

10^{-2}

Option 3)

10^{-1}

Option 4)

10^{-3}

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