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The equation of travelling wave is y = 60\cos(1800t-6x) where y is in microns and t in seconds. The ratio of maximum particle velocity to velocity of wave propagation is

  • Option 1)

    3.6

  • Option 2)

    3.6\times10^{-6}

  • Option 3)

    3.6\times10^{-11}

  • Option 4)

    3.6\times10^{-4}

 

Answers (1)

best_answer

v_{p(max)} = \omega A , wave velocity v_{w} = \frac{\omega }{k} Ratio = \frac{ \omega A}{\omega k} = Ak = 60 X 10^{-6} X 6 \Rightarrow 3.6 X 10^{-4}

 

Speed of sinusoidal wave -

Wave Speed

\tfrac{dx}{dt}= V=\frac{\omega }{k}
 

- wherein

\omega = 2\pi \nu

K= \frac{2\pi }{\lambda }

 

 

 


Option 1)

3.6

This is incorrect.

Option 2)

3.6\times10^{-6}

This is incorrect.

Option 3)

3.6\times10^{-11}

This is incorrect.

Option 4)

3.6\times10^{-4}

This is correct.

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divya.saini

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