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  • Please,please help me - Oscillations and Waves - JEE Main-6

A simple harmonic progressive wave is represented by the equation : y = 8\sin2\pi(0.1x -2t), where x and y are in cm and t is in seconds. At any instant the phase difference between two particles seperated by 2.0 cm in the x-direction is 

  • Option 1)

    18\degree

  • Option 2)

    36\degree

  • Option 3)

    54\degree

  • Option 4)

    72\degree

 

Answers (1)

best_answer

From the giveen equation k = 0.2 \pi

\Rightarrow \frac{2 \pi}{\lambda} = 0.2 \pi \Rightarrow \lambda = 10 cm

\Delta \phi = \frac{2 \pi}{\lambda} \Delta x = \frac{2 \pi}{10} X2 = \frac{2 \pi}{5} = 72^{o}

 

In phase and out of phase -

\Delta x= n\lambda \: \: \: or\: \: \Delta \phi = 2n\pi

i.e. point seprated by distance n\lambda are in same phase.

\Delta x= \frac{m\lambda }{2}\left ( m= 1,3,5,7...... \right )\\\ or \: \Delta \phi = m\pi

Point separated by \frac{m\lambda }{2} are out of phase.

-

 

 

 


Option 1)

18\degree

This is incorrect.

Option 2)

36\degree

This is incorrect.

Option 3)

54\degree

This is incorrect.

Option 4)

72\degree

This is correct.

Posted by

Aadil

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